How to remove the last line-feed raised by foreach
As the following example showes, there are an extra line-feed which is not needed. Is there a way to eliminate?
Example:
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach x in mylist {%
makebox[4em][s]{x}\%
}%
}
}
end{document}
minipage parbox
add a comment |
As the following example showes, there are an extra line-feed which is not needed. Is there a way to eliminate?
Example:
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach x in mylist {%
makebox[4em][s]{x}\%
}%
}
}
end{document}
minipage parbox
add a comment |
As the following example showes, there are an extra line-feed which is not needed. Is there a way to eliminate?
Example:
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach x in mylist {%
makebox[4em][s]{x}\%
}%
}
}
end{document}
minipage parbox
As the following example showes, there are an extra line-feed which is not needed. Is there a way to eliminate?
Example:
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach x in mylist {%
makebox[4em][s]{x}\%
}%
}
}
end{document}
minipage parbox
minipage parbox
asked 2 hours ago
lyllyl
54828
54828
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
A listofitems
alternative...
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
makebox[4em][l]{x}%
ifnumxcnt<mylistlenrelax\fi%
}%
}%
}
end{document}
or switch the test order:
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
ifnumxcnt=1relaxelse\fi%
makebox[4em][l]{x}%
}%
}%
}
end{document}
You give me a new way. Thank you!
– lyl
3 mins ago
add a comment |
The problem is that you issue a \
at the end of each line. You can avoid it e.g. with
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach X [count=Y]in mylist {%
ifnumY=1
makebox[4em][s]{X}
else
\ makebox[4em][s]{X}%
fi
}%
}
}
end{document}
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
A listofitems
alternative...
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
makebox[4em][l]{x}%
ifnumxcnt<mylistlenrelax\fi%
}%
}%
}
end{document}
or switch the test order:
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
ifnumxcnt=1relaxelse\fi%
makebox[4em][l]{x}%
}%
}%
}
end{document}
You give me a new way. Thank you!
– lyl
3 mins ago
add a comment |
A listofitems
alternative...
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
makebox[4em][l]{x}%
ifnumxcnt<mylistlenrelax\fi%
}%
}%
}
end{document}
or switch the test order:
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
ifnumxcnt=1relaxelse\fi%
makebox[4em][l]{x}%
}%
}%
}
end{document}
You give me a new way. Thank you!
– lyl
3 mins ago
add a comment |
A listofitems
alternative...
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
makebox[4em][l]{x}%
ifnumxcnt<mylistlenrelax\fi%
}%
}%
}
end{document}
or switch the test order:
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
ifnumxcnt=1relaxelse\fi%
makebox[4em][l]{x}%
}%
}%
}
end{document}
A listofitems
alternative...
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
makebox[4em][l]{x}%
ifnumxcnt<mylistlenrelax\fi%
}%
}%
}
end{document}
or switch the test order:
documentclass{article}
usepackage{listofitems}
begin{document}
readlist*mylist{str1,str2,str3}
framebox{%
parbox{4em}{%
foreachitemxinmylist{%
ifnumxcnt=1relaxelse\fi%
makebox[4em][l]{x}%
}%
}%
}
end{document}
edited 1 hour ago
answered 2 hours ago
Steven B. SegletesSteven B. Segletes
155k9200409
155k9200409
You give me a new way. Thank you!
– lyl
3 mins ago
add a comment |
You give me a new way. Thank you!
– lyl
3 mins ago
You give me a new way. Thank you!
– lyl
3 mins ago
You give me a new way. Thank you!
– lyl
3 mins ago
add a comment |
The problem is that you issue a \
at the end of each line. You can avoid it e.g. with
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach X [count=Y]in mylist {%
ifnumY=1
makebox[4em][s]{X}
else
\ makebox[4em][s]{X}%
fi
}%
}
}
end{document}
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
add a comment |
The problem is that you issue a \
at the end of each line. You can avoid it e.g. with
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach X [count=Y]in mylist {%
ifnumY=1
makebox[4em][s]{X}
else
\ makebox[4em][s]{X}%
fi
}%
}
}
end{document}
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
add a comment |
The problem is that you issue a \
at the end of each line. You can avoid it e.g. with
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach X [count=Y]in mylist {%
ifnumY=1
makebox[4em][s]{X}
else
\ makebox[4em][s]{X}%
fi
}%
}
}
end{document}
The problem is that you issue a \
at the end of each line. You can avoid it e.g. with
documentclass{article}
usepackage{tikz}
begin{document}
defmylist{str1,str2,str3}
framebox{
parbox{4em}{%
foreach X [count=Y]in mylist {%
ifnumY=1
makebox[4em][s]{X}
else
\ makebox[4em][s]{X}%
fi
}%
}
}
end{document}
answered 37 mins ago
marmotmarmot
101k4116223
101k4116223
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
add a comment |
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
1
1
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
A simple and exactly what I want solution! Thank you!
– lyl
4 mins ago
add a comment |
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