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Why do variable in an inner function return nan when there is the same variable name at the inner function...

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7 1 What's happening here? I get a different result if I declare a variable after console.log in the inner function I understand that var has a functional scope and inner function can access the variable from their parent function outer() { var a = 2; function inner() { a++; console.log(a) //log NaN var a = 8 } inner() } outer() function outer() { var a = 2; function inner() { a++; console.log(a) //log 3 var b = 8 } inner() } outer() The log returns NaN in the first example and log 3 in the second example javascript function share | improve this question ...