How to fade a semiplane defined by line?












3















With the following code:



documentclass[tikz]{standalone}

usepackage{tkz-euclide,tkz-fct,amsmath}
usetkzobj{all}


begin{document}
begin{tikzpicture}[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}

tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
tkzDrawY[noticks, label={(operatorname{Im}(x) )}]

tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]{x-.5}
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)

tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
end{tikzpicture}
end{document}


I'm getting:



enter image description here



I wanted to add a fade like this:



enter image description here



but I can't have the fade to be in the right angle.



How can I get this kind of fade, fadding to white?










share|improve this question



























    3















    With the following code:



    documentclass[tikz]{standalone}

    usepackage{tkz-euclide,tkz-fct,amsmath}
    usetkzobj{all}


    begin{document}
    begin{tikzpicture}[anchor=center]
    tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
    tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}

    tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
    tkzDrawY[noticks, label={(operatorname{Im}(x) )}]

    tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
    tkzMarkRightAngle(A,M,P_1)
    tkzFct[domain=-1:3, color=red, thick]{x-.5}
    draw (P_1) -- (P_2);
    tkzLabelPoints[above right](P_1,P_2)
    tkzLabelPoints[right](M)

    tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
    end{tikzpicture}
    end{document}


    I'm getting:



    enter image description here



    I wanted to add a fade like this:



    enter image description here



    but I can't have the fade to be in the right angle.



    How can I get this kind of fade, fadding to white?










    share|improve this question

























      3












      3








      3








      With the following code:



      documentclass[tikz]{standalone}

      usepackage{tkz-euclide,tkz-fct,amsmath}
      usetkzobj{all}


      begin{document}
      begin{tikzpicture}[anchor=center]
      tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
      tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}

      tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
      tkzDrawY[noticks, label={(operatorname{Im}(x) )}]

      tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
      tkzMarkRightAngle(A,M,P_1)
      tkzFct[domain=-1:3, color=red, thick]{x-.5}
      draw (P_1) -- (P_2);
      tkzLabelPoints[above right](P_1,P_2)
      tkzLabelPoints[right](M)

      tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
      end{tikzpicture}
      end{document}


      I'm getting:



      enter image description here



      I wanted to add a fade like this:



      enter image description here



      but I can't have the fade to be in the right angle.



      How can I get this kind of fade, fadding to white?










      share|improve this question














      With the following code:



      documentclass[tikz]{standalone}

      usepackage{tkz-euclide,tkz-fct,amsmath}
      usetkzobj{all}


      begin{document}
      begin{tikzpicture}[anchor=center]
      tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
      tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}

      tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
      tkzDrawY[noticks, label={(operatorname{Im}(x) )}]

      tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
      tkzMarkRightAngle(A,M,P_1)
      tkzFct[domain=-1:3, color=red, thick]{x-.5}
      draw (P_1) -- (P_2);
      tkzLabelPoints[above right](P_1,P_2)
      tkzLabelPoints[right](M)

      tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
      end{tikzpicture}
      end{document}


      I'm getting:



      enter image description here



      I wanted to add a fade like this:



      enter image description here



      but I can't have the fade to be in the right angle.



      How can I get this kind of fade, fadding to white?







      tikz-pgf tkz-euclide






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 5 hours ago









      Concept7Concept7

      916




      916






















          2 Answers
          2






          active

          oldest

          votes


















          4














          You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



          enter image description here



          documentclass[tikz,border=5mm]{standalone}
          usepackage{tkz-euclide}
          usetkzobj{all}
          begin{document}
          begin{tikzpicture}
          coordinate[label=above right:$P_1$] (P1) at (.5,2);
          coordinate[label=above right:$P_2$] (P2) at (2.5,0);
          coordinate[label=right:$M$] (M) at (1.5,1);
          coordinate (A) at (2,1.5);
          pgfmathsetmacro{a}{.5-sqrt(2)}
          pgfmathsetmacro{b}{.5+sqrt(12.5)}

          shade[top color=white,bottom color=red!50,
          transform canvas={rotate around={45:(.5,0)}}]
          (a,0) rectangle (b,.5);
          draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
          draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};

          draw (P1) -- (P2);
          draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
          foreach p in {P1,P2,M}
          fill (p) circle(1pt);
          node at (1.5,3){(|z-z_1|leq|z-z_2| )};
          tkzMarkRightAngle(P1,M,A)
          end{tikzpicture}
          end{document}





          share|improve this answer































            2














            This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



            documentclass[tikz]{standalone}
            usetikzlibrary{calc,backgrounds}
            usepackage{amsmath}
            DeclareMathOperator{re}{Re}
            DeclareMathOperator{im}{Im}
            begin{document}
            begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
            xmin=-1;xmax=3;}]
            draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
            draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
            path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
            {(X,Y) coordinate[label=P:$L$] (L)};
            begin{scope}[on background layer]
            shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
            n1={atan2(y2-y1,x2-x1)} in
            [left color=white,right color=red,middle color=white,shading angle=n1]
            (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
            ;
            end{scope}
            draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
            draw (P_1) -- (P_2);
            node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • I like your answer, and the correction of re(x) and im(x) :).

              – manooooh
              8 mins ago











            Your Answer








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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



            enter image description here



            documentclass[tikz,border=5mm]{standalone}
            usepackage{tkz-euclide}
            usetkzobj{all}
            begin{document}
            begin{tikzpicture}
            coordinate[label=above right:$P_1$] (P1) at (.5,2);
            coordinate[label=above right:$P_2$] (P2) at (2.5,0);
            coordinate[label=right:$M$] (M) at (1.5,1);
            coordinate (A) at (2,1.5);
            pgfmathsetmacro{a}{.5-sqrt(2)}
            pgfmathsetmacro{b}{.5+sqrt(12.5)}

            shade[top color=white,bottom color=red!50,
            transform canvas={rotate around={45:(.5,0)}}]
            (a,0) rectangle (b,.5);
            draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
            draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};

            draw (P1) -- (P2);
            draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
            foreach p in {P1,P2,M}
            fill (p) circle(1pt);
            node at (1.5,3){(|z-z_1|leq|z-z_2| )};
            tkzMarkRightAngle(P1,M,A)
            end{tikzpicture}
            end{document}





            share|improve this answer




























              4














              You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



              enter image description here



              documentclass[tikz,border=5mm]{standalone}
              usepackage{tkz-euclide}
              usetkzobj{all}
              begin{document}
              begin{tikzpicture}
              coordinate[label=above right:$P_1$] (P1) at (.5,2);
              coordinate[label=above right:$P_2$] (P2) at (2.5,0);
              coordinate[label=right:$M$] (M) at (1.5,1);
              coordinate (A) at (2,1.5);
              pgfmathsetmacro{a}{.5-sqrt(2)}
              pgfmathsetmacro{b}{.5+sqrt(12.5)}

              shade[top color=white,bottom color=red!50,
              transform canvas={rotate around={45:(.5,0)}}]
              (a,0) rectangle (b,.5);
              draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
              draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};

              draw (P1) -- (P2);
              draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
              foreach p in {P1,P2,M}
              fill (p) circle(1pt);
              node at (1.5,3){(|z-z_1|leq|z-z_2| )};
              tkzMarkRightAngle(P1,M,A)
              end{tikzpicture}
              end{document}





              share|improve this answer


























                4












                4








                4







                You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



                enter image description here



                documentclass[tikz,border=5mm]{standalone}
                usepackage{tkz-euclide}
                usetkzobj{all}
                begin{document}
                begin{tikzpicture}
                coordinate[label=above right:$P_1$] (P1) at (.5,2);
                coordinate[label=above right:$P_2$] (P2) at (2.5,0);
                coordinate[label=right:$M$] (M) at (1.5,1);
                coordinate (A) at (2,1.5);
                pgfmathsetmacro{a}{.5-sqrt(2)}
                pgfmathsetmacro{b}{.5+sqrt(12.5)}

                shade[top color=white,bottom color=red!50,
                transform canvas={rotate around={45:(.5,0)}}]
                (a,0) rectangle (b,.5);
                draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
                draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};

                draw (P1) -- (P2);
                draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
                foreach p in {P1,P2,M}
                fill (p) circle(1pt);
                node at (1.5,3){(|z-z_1|leq|z-z_2| )};
                tkzMarkRightAngle(P1,M,A)
                end{tikzpicture}
                end{document}





                share|improve this answer













                You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'



                enter image description here



                documentclass[tikz,border=5mm]{standalone}
                usepackage{tkz-euclide}
                usetkzobj{all}
                begin{document}
                begin{tikzpicture}
                coordinate[label=above right:$P_1$] (P1) at (.5,2);
                coordinate[label=above right:$P_2$] (P2) at (2.5,0);
                coordinate[label=right:$M$] (M) at (1.5,1);
                coordinate (A) at (2,1.5);
                pgfmathsetmacro{a}{.5-sqrt(2)}
                pgfmathsetmacro{b}{.5+sqrt(12.5)}

                shade[top color=white,bottom color=red!50,
                transform canvas={rotate around={45:(.5,0)}}]
                (a,0) rectangle (b,.5);
                draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
                draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};

                draw (P1) -- (P2);
                draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
                foreach p in {P1,P2,M}
                fill (p) circle(1pt);
                node at (1.5,3){(|z-z_1|leq|z-z_2| )};
                tkzMarkRightAngle(P1,M,A)
                end{tikzpicture}
                end{document}






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 4 hours ago









                Black MildBlack Mild

                697611




                697611























                    2














                    This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                    documentclass[tikz]{standalone}
                    usetikzlibrary{calc,backgrounds}
                    usepackage{amsmath}
                    DeclareMathOperator{re}{Re}
                    DeclareMathOperator{im}{Im}
                    begin{document}
                    begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
                    xmin=-1;xmax=3;}]
                    draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
                    draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
                    path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
                    {(X,Y) coordinate[label=P:$L$] (L)};
                    begin{scope}[on background layer]
                    shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
                    n1={atan2(y2-y1,x2-x1)} in
                    [left color=white,right color=red,middle color=white,shading angle=n1]
                    (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                    ;
                    end{scope}
                    draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
                    draw (P_1) -- (P_2);
                    node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
                    end{tikzpicture}
                    end{document}


                    enter image description here






                    share|improve this answer


























                    • I like your answer, and the correction of re(x) and im(x) :).

                      – manooooh
                      8 mins ago
















                    2














                    This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                    documentclass[tikz]{standalone}
                    usetikzlibrary{calc,backgrounds}
                    usepackage{amsmath}
                    DeclareMathOperator{re}{Re}
                    DeclareMathOperator{im}{Im}
                    begin{document}
                    begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
                    xmin=-1;xmax=3;}]
                    draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
                    draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
                    path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
                    {(X,Y) coordinate[label=P:$L$] (L)};
                    begin{scope}[on background layer]
                    shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
                    n1={atan2(y2-y1,x2-x1)} in
                    [left color=white,right color=red,middle color=white,shading angle=n1]
                    (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                    ;
                    end{scope}
                    draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
                    draw (P_1) -- (P_2);
                    node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
                    end{tikzpicture}
                    end{document}


                    enter image description here






                    share|improve this answer


























                    • I like your answer, and the correction of re(x) and im(x) :).

                      – manooooh
                      8 mins ago














                    2












                    2








                    2







                    This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                    documentclass[tikz]{standalone}
                    usetikzlibrary{calc,backgrounds}
                    usepackage{amsmath}
                    DeclareMathOperator{re}{Re}
                    DeclareMathOperator{im}{Im}
                    begin{document}
                    begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
                    xmin=-1;xmax=3;}]
                    draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
                    draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
                    path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
                    {(X,Y) coordinate[label=P:$L$] (L)};
                    begin{scope}[on background layer]
                    shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
                    n1={atan2(y2-y1,x2-x1)} in
                    [left color=white,right color=red,middle color=white,shading angle=n1]
                    (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                    ;
                    end{scope}
                    draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
                    draw (P_1) -- (P_2);
                    node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
                    end{tikzpicture}
                    end{document}


                    enter image description here






                    share|improve this answer















                    This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.



                    documentclass[tikz]{standalone}
                    usetikzlibrary{calc,backgrounds}
                    usepackage{amsmath}
                    DeclareMathOperator{re}{Re}
                    DeclareMathOperator{im}{Im}
                    begin{document}
                    begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
                    xmin=-1;xmax=3;}]
                    draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
                    draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
                    path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
                    {(X,Y) coordinate[label=P:$L$] (L)};
                    begin{scope}[on background layer]
                    shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
                    n1={atan2(y2-y1,x2-x1)} in
                    [left color=white,right color=red,middle color=white,shading angle=n1]
                    (p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
                    ;
                    end{scope}
                    draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
                    draw (P_1) -- (P_2);
                    node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
                    end{tikzpicture}
                    end{document}


                    enter image description here







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 3 hours ago

























                    answered 4 hours ago









                    marmotmarmot

                    111k5138257




                    111k5138257













                    • I like your answer, and the correction of re(x) and im(x) :).

                      – manooooh
                      8 mins ago



















                    • I like your answer, and the correction of re(x) and im(x) :).

                      – manooooh
                      8 mins ago

















                    I like your answer, and the correction of re(x) and im(x) :).

                    – manooooh
                    8 mins ago





                    I like your answer, and the correction of re(x) and im(x) :).

                    – manooooh
                    8 mins ago


















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