How to fade a semiplane defined by line?
With the following code:
documentclass[tikz]{standalone}
usepackage{tkz-euclide,tkz-fct,amsmath}
usetkzobj{all}
begin{document}
begin{tikzpicture}[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}
tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
tkzDrawY[noticks, label={(operatorname{Im}(x) )}]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]{x-.5}
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
end{tikzpicture}
end{document}
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
add a comment |
With the following code:
documentclass[tikz]{standalone}
usepackage{tkz-euclide,tkz-fct,amsmath}
usetkzobj{all}
begin{document}
begin{tikzpicture}[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}
tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
tkzDrawY[noticks, label={(operatorname{Im}(x) )}]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]{x-.5}
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
end{tikzpicture}
end{document}
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
add a comment |
With the following code:
documentclass[tikz]{standalone}
usepackage{tkz-euclide,tkz-fct,amsmath}
usetkzobj{all}
begin{document}
begin{tikzpicture}[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}
tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
tkzDrawY[noticks, label={(operatorname{Im}(x) )}]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]{x-.5}
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
end{tikzpicture}
end{document}
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
With the following code:
documentclass[tikz]{standalone}
usepackage{tkz-euclide,tkz-fct,amsmath}
usetkzobj{all}
begin{document}
begin{tikzpicture}[anchor=center]
tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]
tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}
tkzDrawX[noticks, label={(operatorname{Re}(x) )}]
tkzDrawY[noticks, label={(operatorname{Im}(x) )}]
tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)
tkzMarkRightAngle(A,M,P_1)
tkzFct[domain=-1:3, color=red, thick]{x-.5}
draw (P_1) -- (P_2);
tkzLabelPoints[above right](P_1,P_2)
tkzLabelPoints[right](M)
tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}
end{tikzpicture}
end{document}
I'm getting:
I wanted to add a fade like this:
but I can't have the fade to be in the right angle.
How can I get this kind of fade, fadding to white?
tikz-pgf tkz-euclide
tikz-pgf tkz-euclide
asked 5 hours ago
Concept7Concept7
916
916
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]{standalone}
usepackage{tkz-euclide}
usetkzobj{all}
begin{document}
begin{tikzpicture}
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacro{a}{.5-sqrt(2)}
pgfmathsetmacro{b}{.5+sqrt(12.5)}
shade[top color=white,bottom color=red!50,
transform canvas={rotate around={45:(.5,0)}}]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
foreach p in {P1,P2,M}
fill (p) circle(1pt);
node at (1.5,3){(|z-z_1|leq|z-z_2| )};
tkzMarkRightAngle(P1,M,A)
end{tikzpicture}
end{document}
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]{standalone}
usetikzlibrary{calc,backgrounds}
usepackage{amsmath}
DeclareMathOperator{re}{Re}
DeclareMathOperator{im}{Im}
begin{document}
begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
xmin=-1;xmax=3;}]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
{(X,Y) coordinate[label=P:$L$] (L)};
begin{scope}[on background layer]
shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
n1={atan2(y2-y1,x2-x1)} in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
end{scope}
draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
end{tikzpicture}
end{document}
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
8 mins ago
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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oldest
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oldest
votes
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]{standalone}
usepackage{tkz-euclide}
usetkzobj{all}
begin{document}
begin{tikzpicture}
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacro{a}{.5-sqrt(2)}
pgfmathsetmacro{b}{.5+sqrt(12.5)}
shade[top color=white,bottom color=red!50,
transform canvas={rotate around={45:(.5,0)}}]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
foreach p in {P1,P2,M}
fill (p) circle(1pt);
node at (1.5,3){(|z-z_1|leq|z-z_2| )};
tkzMarkRightAngle(P1,M,A)
end{tikzpicture}
end{document}
add a comment |
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]{standalone}
usepackage{tkz-euclide}
usetkzobj{all}
begin{document}
begin{tikzpicture}
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacro{a}{.5-sqrt(2)}
pgfmathsetmacro{b}{.5+sqrt(12.5)}
shade[top color=white,bottom color=red!50,
transform canvas={rotate around={45:(.5,0)}}]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
foreach p in {P1,P2,M}
fill (p) circle(1pt);
node at (1.5,3){(|z-z_1|leq|z-z_2| )};
tkzMarkRightAngle(P1,M,A)
end{tikzpicture}
end{document}
add a comment |
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]{standalone}
usepackage{tkz-euclide}
usetkzobj{all}
begin{document}
begin{tikzpicture}
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacro{a}{.5-sqrt(2)}
pgfmathsetmacro{b}{.5+sqrt(12.5)}
shade[top color=white,bottom color=red!50,
transform canvas={rotate around={45:(.5,0)}}]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
foreach p in {P1,P2,M}
fill (p) circle(1pt);
node at (1.5,3){(|z-z_1|leq|z-z_2| )};
tkzMarkRightAngle(P1,M,A)
end{tikzpicture}
end{document}
You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'
documentclass[tikz,border=5mm]{standalone}
usepackage{tkz-euclide}
usetkzobj{all}
begin{document}
begin{tikzpicture}
coordinate[label=above right:$P_1$] (P1) at (.5,2);
coordinate[label=above right:$P_2$] (P2) at (2.5,0);
coordinate[label=right:$M$] (M) at (1.5,1);
coordinate (A) at (2,1.5);
pgfmathsetmacro{a}{.5-sqrt(2)}
pgfmathsetmacro{b}{.5+sqrt(12.5)}
shade[top color=white,bottom color=red!50,
transform canvas={rotate around={45:(.5,0)}}]
(a,0) rectangle (b,.5);
draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};
draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};
draw (P1) -- (P2);
draw[red,thick] plot[domain=-.5:3] (x,{x-.5});
foreach p in {P1,P2,M}
fill (p) circle(1pt);
node at (1.5,3){(|z-z_1|leq|z-z_2| )};
tkzMarkRightAngle(P1,M,A)
end{tikzpicture}
end{document}
answered 4 hours ago
Black MildBlack Mild
697611
697611
add a comment |
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]{standalone}
usetikzlibrary{calc,backgrounds}
usepackage{amsmath}
DeclareMathOperator{re}{Re}
DeclareMathOperator{im}{Im}
begin{document}
begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
xmin=-1;xmax=3;}]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
{(X,Y) coordinate[label=P:$L$] (L)};
begin{scope}[on background layer]
shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
n1={atan2(y2-y1,x2-x1)} in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
end{scope}
draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
end{tikzpicture}
end{document}
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
8 mins ago
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]{standalone}
usetikzlibrary{calc,backgrounds}
usepackage{amsmath}
DeclareMathOperator{re}{Re}
DeclareMathOperator{im}{Im}
begin{document}
begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
xmin=-1;xmax=3;}]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
{(X,Y) coordinate[label=P:$L$] (L)};
begin{scope}[on background layer]
shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
n1={atan2(y2-y1,x2-x1)} in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
end{scope}
draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
end{tikzpicture}
end{document}
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
8 mins ago
add a comment |
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]{standalone}
usetikzlibrary{calc,backgrounds}
usepackage{amsmath}
DeclareMathOperator{re}{Re}
DeclareMathOperator{im}{Im}
begin{document}
begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
xmin=-1;xmax=3;}]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
{(X,Y) coordinate[label=P:$L$] (L)};
begin{scope}[on background layer]
shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
n1={atan2(y2-y1,x2-x1)} in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
end{scope}
draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
end{tikzpicture}
end{document}
This is in principle very simple but tkz-euclide
seems to mess up things a bit. One can just use a shading angle
, which can, of course, be computed by TikZ.
documentclass[tikz]{standalone}
usetikzlibrary{calc,backgrounds}
usepackage{amsmath}
DeclareMathOperator{re}{Re}
DeclareMathOperator{im}{Im}
begin{document}
begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;
xmin=-1;xmax=3;}]
draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};
draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;
path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}
{(X,Y) coordinate[label=P:$L$] (L)};
begin{scope}[on background layer]
shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),
n1={atan2(y2-y1,x2-x1)} in
[left color=white,right color=red,middle color=white,shading angle=n1]
(p1) -- (p2) -- ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)
;
end{scope}
draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});
draw (P_1) -- (P_2);
node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};
end{tikzpicture}
end{document}
edited 3 hours ago
answered 4 hours ago
marmotmarmot
111k5138257
111k5138257
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
8 mins ago
add a comment |
I like your answer, and the correction ofre(x)
andim(x)
:).
– manooooh
8 mins ago
I like your answer, and the correction of
re(x)
and im(x)
:).– manooooh
8 mins ago
I like your answer, and the correction of
re(x)
and im(x)
:).– manooooh
8 mins ago
add a comment |
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