Applying a function to a nested list
$begingroup$
Say I have a list:
l = {{{a, b}, c}, d}
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[{F[{F[{a,b}], c}] , d}]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked 2 hours ago
amator2357amator2357
4538
$endgroup$
add a comment |
$begingroup$
Say I have a list:
l = {{{a, b}, c}, d}
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[{F[{F[{a,b}], c}] , d}]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked 2 hours ago
amator2357amator2357
4538
$endgroup$
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
2 hours ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago
add a comment |
$begingroup$
Say I have a list:
l = {{{a, b}, c}, d}
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[{F[{F[{a,b}], c}] , d}]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
asked 2 hours ago
amator2357amator2357
4538
$endgroup$
Say I have a list:
l = {{{a, b}, c}, d}
I now want to apply a function, call it F to that list in a way that I go from the lowest to highest level, i.e.
F[{F[{F[{a,b}], c}] , d}]
Is there a function in Mathematica which does exactly that?
list-manipulation functions
list-manipulation functions
asked 2 hours ago
amator2357amator2357
4538
asked 2 hours ago
amator2357amator2357
4538
edited 1 hour ago
amator2357
asked 2 hours ago
amator2357amator2357
4538
asked 2 hours ago
amator2357amator2357
4538
asked 2 hours ago
amator2357amator2357
4538
4538
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
2 hours ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago
add a comment |
4
$begingroup$
Why does the order fordandcchange, and not foraandb?
$endgroup$
– Carl Woll
2 hours ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago
4
4
$begingroup$
Why does the order for
d and c change, and not for a and b?$endgroup$
– Carl Woll
2 hours ago
$begingroup$
Why does the order for
d and c change, and not for a and b?$endgroup$
– Carl Woll
2 hours ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
Replace[l, x_List :> F[x], All]
F[{F[{F[{a, b}], c}], d}]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[{f[{f[{a, b}], c}], d}]
answered 1 hour ago
kglrkglr
190k10209427
$endgroup$
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[{d, F[{c, F[{b, a}]}]}]
Fold[F[{#2, #1}] &, Flatten[l]]
F[{d, F[{c, F[{b, a}]}]}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
This works:
{{{a, b}, c}, d} //. {{s_?ListQ, t_?(Not@*ListQ)} :> {f[s], t}} // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered 1 hour ago
ShredderroyShredderroy
1,6101117
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[{F[{F[{a, b}], c}], d}]
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Replace[l, x_List :> F[x], All]
F[{F[{F[{a, b}], c}], d}]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[{f[{f[{a, b}], c}], d}]
answered 1 hour ago
kglrkglr
190k10209427
$endgroup$
add a comment |
$begingroup$
Replace[l, x_List :> F[x], All]
F[{F[{F[{a, b}], c}], d}]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[{f[{f[{a, b}], c}], d}]
answered 1 hour ago
kglrkglr
190k10209427
$endgroup$
add a comment |
$begingroup$
Replace[l, x_List :> F[x], All]
F[{F[{F[{a, b}], c}], d}]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[{f[{f[{a, b}], c}], d}]
answered 1 hour ago
kglrkglr
190k10209427
$endgroup$
Replace[l, x_List :> F[x], All]
F[{F[{F[{a, b}], c}], d}]
Also
ClearAll[f]
f[Except[_List, x_]] := x;
MapAll[f, l]
f[{f[{f[{a, b}], c}], d}]
answered 1 hour ago
kglrkglr
190k10209427
answered 1 hour ago
kglrkglr
190k10209427
answered 1 hour ago
kglrkglr
190k10209427
answered 1 hour ago
kglrkglr
190k10209427
190k10209427
add a comment |
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[{d, F[{c, F[{b, a}]}]}]
Fold[F[{#2, #1}] &, Flatten[l]]
F[{d, F[{c, F[{b, a}]}]}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[{d, F[{c, F[{b, a}]}]}]
Fold[F[{#2, #1}] &, Flatten[l]]
F[{d, F[{c, F[{b, a}]}]}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
$endgroup$
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[{d, F[{c, F[{b, a}]}]}]
Fold[F[{#2, #1}] &, Flatten[l]]
F[{d, F[{c, F[{b, a}]}]}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
$endgroup$
F@*Reverse@Map[F@*Reverse, l, -2]
F[{d, F[{c, F[{b, a}]}]}]
Fold[F[{#2, #1}] &, Flatten[l]]
F[{d, F[{c, F[{b, a}]}]}]
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
61.3k585171
61.3k585171
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
I think thatFlattenworks in this trivial case but it will not "find" the levels in a more complex situation
$endgroup$
– J42161217
1 hour ago
$begingroup$
I think that
Flatten works in this trivial case but it will not "find" the levels in a more complex situation$endgroup$
– J42161217
1 hour ago
$begingroup$
I think that
Flatten works in this trivial case but it will not "find" the levels in a more complex situation$endgroup$
– J42161217
1 hour ago
add a comment |
$begingroup$
This works:
{{{a, b}, c}, d} //. {{s_?ListQ, t_?(Not@*ListQ)} :> {f[s], t}} // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered 1 hour ago
ShredderroyShredderroy
1,6101117
$endgroup$
add a comment |
$begingroup$
This works:
{{{a, b}, c}, d} //. {{s_?ListQ, t_?(Not@*ListQ)} :> {f[s], t}} // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered 1 hour ago
ShredderroyShredderroy
1,6101117
$endgroup$
add a comment |
$begingroup$
This works:
{{{a, b}, c}, d} //. {{s_?ListQ, t_?(Not@*ListQ)} :> {f[s], t}} // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered 1 hour ago
ShredderroyShredderroy
1,6101117
$endgroup$
This works:
{{{a, b}, c}, d} //. {{s_?ListQ, t_?(Not@*ListQ)} :> {f[s], t}} // f
It's a bit hackish because of the separate invocation of f at the end, but it returns the desired result.
answered 1 hour ago
ShredderroyShredderroy
1,6101117
answered 1 hour ago
ShredderroyShredderroy
1,6101117
answered 1 hour ago
ShredderroyShredderroy
1,6101117
answered 1 hour ago
ShredderroyShredderroy
1,6101117
1,6101117
add a comment |
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[{F[{F[{a, b}], c}], d}]
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[{F[{F[{a, b}], c}], d}]
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
$endgroup$
add a comment |
$begingroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[{F[{F[{a, b}], c}], d}]
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
$endgroup$
Another possibility, if you want just lists to acquire the F wrapper:
l /. List -> F@*List
F[{F[{F[{a, b}], c}], d}]
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
answered 27 mins ago
Carl WollCarl Woll
76.4k3100200
76.4k3100200
add a comment |
add a comment |
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4
$begingroup$
Why does the order for
dandcchange, and not foraandb?$endgroup$
– Carl Woll
2 hours ago
$begingroup$
My mistake, thank you for spotting that. I edited it.
$endgroup$
– amator2357
1 hour ago