How can an equation having ColorDistance function be solved?
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I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 19 hours ago
MajisMajis
1,477415
$endgroup$
add a comment |
$begingroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 19 hours ago
MajisMajis
1,477415
$endgroup$
add a comment |
$begingroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 19 hours ago
MajisMajis
1,477415
$endgroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
list-manipulation equation-solving color
asked 19 hours ago
MajisMajis
1,477415
asked 19 hours ago
MajisMajis
1,477415
asked 19 hours ago
MajisMajis
1,477415
asked 19 hours ago
MajisMajis
1,477415
asked 19 hours ago
MajisMajis
1,477415
1,477415
add a comment |
add a comment |
1 Answer
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$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
add a comment |
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1 Answer
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1 Answer
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$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
add a comment |
$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
add a comment |
$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
$endgroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
answered 19 hours ago
SzabolcsSzabolcs
163k14447944
163k14447944
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
add a comment |
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
18 hours ago
add a comment |
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