Evaluating number of iteration with a certain map with While












2












$begingroup$


Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.



I am trying to solve the following problem:



Given the map $z_{i+1}= z_i^2 +c$ with $z_i, c in mathbb{C}$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.



Given the condition I though I could use a While Loop to perform the task



i=0;            (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]


This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)



Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.



Thanks in advance to everyone who is so keen to stop by and help :)










share|improve this question







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  • $begingroup$
    Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
    $endgroup$
    – Kiro
    22 hours ago
















2












$begingroup$


Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.



I am trying to solve the following problem:



Given the map $z_{i+1}= z_i^2 +c$ with $z_i, c in mathbb{C}$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.



Given the condition I though I could use a While Loop to perform the task



i=0;            (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]


This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)



Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.



Thanks in advance to everyone who is so keen to stop by and help :)










share|improve this question







New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
    $endgroup$
    – Kiro
    22 hours ago














2












2








2





$begingroup$


Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.



I am trying to solve the following problem:



Given the map $z_{i+1}= z_i^2 +c$ with $z_i, c in mathbb{C}$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.



Given the condition I though I could use a While Loop to perform the task



i=0;            (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]


This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)



Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.



Thanks in advance to everyone who is so keen to stop by and help :)










share|improve this question







New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.



I am trying to solve the following problem:



Given the map $z_{i+1}= z_i^2 +c$ with $z_i, c in mathbb{C}$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.



Given the condition I though I could use a While Loop to perform the task



i=0;            (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]


This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)



Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.



Thanks in advance to everyone who is so keen to stop by and help :)







procedural-programming






share|improve this question







New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









JacquesLeenJacquesLeen

303




303




New contributor




JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
    $endgroup$
    – Kiro
    22 hours ago


















  • $begingroup$
    Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
    $endgroup$
    – Kiro
    22 hours ago
















$begingroup$
Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
$endgroup$
– Kiro
22 hours ago




$begingroup$
Hello there. Just wanted to point out that for the input you give as example the computation will never finish because the condition is always satisfied. The absolute value never goes above 0.36.
$endgroup$
– Kiro
22 hours ago










3 Answers
3






active

oldest

votes


















7












$begingroup$

The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.





For this type of iteration, the typical function to use is Nest and related functions.



countIter[c_] := 
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]

result =
Table[
countIter[re + im I],
{re, -0.6, -0.4, 0.2/100},
{im, 0.4, 0.6, 0.2/100}
];

ArrayPlot[result, ColorFunction -> "Rainbow"]


enter image description here





However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).



countIterCompiled = Compile[{{c, _Complex}},
Block[{z = 0.0 + 0.0 I, i = 0},
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]


Using countIterCompiled will be much faster than countIter.






share|improve this answer











$endgroup$













  • $begingroup$
    thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
    $endgroup$
    – JacquesLeen
    yesterday










  • $begingroup$
    @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
    $endgroup$
    – Szabolcs
    yesterday



















3












$begingroup$

For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:



f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* {0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349} *)


As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.






share|improve this answer









$endgroup$





















    1












    $begingroup$

    You could also use MandelbrotSetPlot to create Szabolcs' graphic:



    MandelbrotSetPlot[{-0.6 + 0.4 I, -0.4 + 0.6 I}, PlotLegends -> Automatic]


    enter image description here






    share|improve this answer









    $endgroup$














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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7












      $begingroup$

      The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.





      For this type of iteration, the typical function to use is Nest and related functions.



      countIter[c_] := 
      Length@NestWhileList[
      #^2 + c &,
      0.0,
      Abs[#] <= 2 &,
      1,
      100 (* limit number of iterations to 100 *)
      ]

      result =
      Table[
      countIter[re + im I],
      {re, -0.6, -0.4, 0.2/100},
      {im, 0.4, 0.6, 0.2/100}
      ];

      ArrayPlot[result, ColorFunction -> "Rainbow"]


      enter image description here





      However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).



      countIterCompiled = Compile[{{c, _Complex}},
      Block[{z = 0.0 + 0.0 I, i = 0},
      While[i <= 100 && Abs[z] <= 2,
      z = z^2 + c;
      i++
      ];
      i
      ]
      ]


      Using countIterCompiled will be much faster than countIter.






      share|improve this answer











      $endgroup$













      • $begingroup$
        thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
        $endgroup$
        – JacquesLeen
        yesterday










      • $begingroup$
        @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
        $endgroup$
        – Szabolcs
        yesterday
















      7












      $begingroup$

      The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.





      For this type of iteration, the typical function to use is Nest and related functions.



      countIter[c_] := 
      Length@NestWhileList[
      #^2 + c &,
      0.0,
      Abs[#] <= 2 &,
      1,
      100 (* limit number of iterations to 100 *)
      ]

      result =
      Table[
      countIter[re + im I],
      {re, -0.6, -0.4, 0.2/100},
      {im, 0.4, 0.6, 0.2/100}
      ];

      ArrayPlot[result, ColorFunction -> "Rainbow"]


      enter image description here





      However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).



      countIterCompiled = Compile[{{c, _Complex}},
      Block[{z = 0.0 + 0.0 I, i = 0},
      While[i <= 100 && Abs[z] <= 2,
      z = z^2 + c;
      i++
      ];
      i
      ]
      ]


      Using countIterCompiled will be much faster than countIter.






      share|improve this answer











      $endgroup$













      • $begingroup$
        thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
        $endgroup$
        – JacquesLeen
        yesterday










      • $begingroup$
        @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
        $endgroup$
        – Szabolcs
        yesterday














      7












      7








      7





      $begingroup$

      The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.





      For this type of iteration, the typical function to use is Nest and related functions.



      countIter[c_] := 
      Length@NestWhileList[
      #^2 + c &,
      0.0,
      Abs[#] <= 2 &,
      1,
      100 (* limit number of iterations to 100 *)
      ]

      result =
      Table[
      countIter[re + im I],
      {re, -0.6, -0.4, 0.2/100},
      {im, 0.4, 0.6, 0.2/100}
      ];

      ArrayPlot[result, ColorFunction -> "Rainbow"]


      enter image description here





      However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).



      countIterCompiled = Compile[{{c, _Complex}},
      Block[{z = 0.0 + 0.0 I, i = 0},
      While[i <= 100 && Abs[z] <= 2,
      z = z^2 + c;
      i++
      ];
      i
      ]
      ]


      Using countIterCompiled will be much faster than countIter.






      share|improve this answer











      $endgroup$



      The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.





      For this type of iteration, the typical function to use is Nest and related functions.



      countIter[c_] := 
      Length@NestWhileList[
      #^2 + c &,
      0.0,
      Abs[#] <= 2 &,
      1,
      100 (* limit number of iterations to 100 *)
      ]

      result =
      Table[
      countIter[re + im I],
      {re, -0.6, -0.4, 0.2/100},
      {im, 0.4, 0.6, 0.2/100}
      ];

      ArrayPlot[result, ColorFunction -> "Rainbow"]


      enter image description here





      However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).



      countIterCompiled = Compile[{{c, _Complex}},
      Block[{z = 0.0 + 0.0 I, i = 0},
      While[i <= 100 && Abs[z] <= 2,
      z = z^2 + c;
      i++
      ];
      i
      ]
      ]


      Using countIterCompiled will be much faster than countIter.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited yesterday

























      answered yesterday









      SzabolcsSzabolcs

      164k14448946




      164k14448946












      • $begingroup$
        thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
        $endgroup$
        – JacquesLeen
        yesterday










      • $begingroup$
        @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
        $endgroup$
        – Szabolcs
        yesterday


















      • $begingroup$
        thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
        $endgroup$
        – JacquesLeen
        yesterday










      • $begingroup$
        @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
        $endgroup$
        – Szabolcs
        yesterday
















      $begingroup$
      thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
      $endgroup$
      – JacquesLeen
      yesterday




      $begingroup$
      thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
      $endgroup$
      – JacquesLeen
      yesterday












      $begingroup$
      @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
      $endgroup$
      – Szabolcs
      yesterday




      $begingroup$
      @JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside Compile, Module and Block are the same, I think. (Not outside of it.)
      $endgroup$
      – Szabolcs
      yesterday











      3












      $begingroup$

      For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:



      f[z_, c_] := z^2 + c
      Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
      (* {0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
      0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
      0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
      0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
      0.31349, 0.31349, 0.31349} *)


      As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.






      share|improve this answer









      $endgroup$


















        3












        $begingroup$

        For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:



        f[z_, c_] := z^2 + c
        Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
        (* {0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
        0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
        0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
        0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
        0.31349, 0.31349, 0.31349} *)


        As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.






        share|improve this answer









        $endgroup$
















          3












          3








          3





          $begingroup$

          For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:



          f[z_, c_] := z^2 + c
          Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
          (* {0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
          0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
          0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
          0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
          0.31349, 0.31349, 0.31349} *)


          As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.






          share|improve this answer









          $endgroup$



          For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:



          f[z_, c_] := z^2 + c
          Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
          (* {0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
          0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
          0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
          0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
          0.31349, 0.31349, 0.31349} *)


          As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered yesterday









          John DotyJohn Doty

          7,57811124




          7,57811124























              1












              $begingroup$

              You could also use MandelbrotSetPlot to create Szabolcs' graphic:



              MandelbrotSetPlot[{-0.6 + 0.4 I, -0.4 + 0.6 I}, PlotLegends -> Automatic]


              enter image description here






              share|improve this answer









              $endgroup$


















                1












                $begingroup$

                You could also use MandelbrotSetPlot to create Szabolcs' graphic:



                MandelbrotSetPlot[{-0.6 + 0.4 I, -0.4 + 0.6 I}, PlotLegends -> Automatic]


                enter image description here






                share|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  You could also use MandelbrotSetPlot to create Szabolcs' graphic:



                  MandelbrotSetPlot[{-0.6 + 0.4 I, -0.4 + 0.6 I}, PlotLegends -> Automatic]


                  enter image description here






                  share|improve this answer









                  $endgroup$



                  You could also use MandelbrotSetPlot to create Szabolcs' graphic:



                  MandelbrotSetPlot[{-0.6 + 0.4 I, -0.4 + 0.6 I}, PlotLegends -> Automatic]


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered yesterday









                  Carl WollCarl Woll

                  73.3k398191




                  73.3k398191






















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