Grep remove line with 0 but not 0.2?
I have a file similar to this:
0
0
0.02
0
0
0
0
I want to remove all the lines with a single zero.
I was thinking to use something like:
grep -v "0"
But this also removes the instances of 0.2.
I also saw there is a whole word option -w but this doesn't seem to work either.
How can I remove all lines which are just a single 0 but keep lines which may contain a 0?
grep
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
add a comment |
I have a file similar to this:
0
0
0.02
0
0
0
0
I want to remove all the lines with a single zero.
I was thinking to use something like:
grep -v "0"
But this also removes the instances of 0.2.
I also saw there is a whole word option -w but this doesn't seem to work either.
How can I remove all lines which are just a single 0 but keep lines which may contain a 0?
grep
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
add a comment |
I have a file similar to this:
0
0
0.02
0
0
0
0
I want to remove all the lines with a single zero.
I was thinking to use something like:
grep -v "0"
But this also removes the instances of 0.2.
I also saw there is a whole word option -w but this doesn't seem to work either.
How can I remove all lines which are just a single 0 but keep lines which may contain a 0?
grep
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
I have a file similar to this:
0
0
0.02
0
0
0
0
I want to remove all the lines with a single zero.
I was thinking to use something like:
grep -v "0"
But this also removes the instances of 0.2.
I also saw there is a whole word option -w but this doesn't seem to work either.
How can I remove all lines which are just a single 0 but keep lines which may contain a 0?
grep
grep
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
asked 34 mins ago
Philip KirkbridePhilip Kirkbride
2,47313084
2,47313084
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
grep -vx 0
From man grep:
-x, --line-regexp
Select only those matches that exactly match the whole line.
For a regular expression pattern, this is like parenthesizing
the pattern and then surrounding it with ^ and $.
-w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".
answered 26 mins ago
SparhawkSparhawk
9,74264094
add a comment |
With grep:
grep -v "^0$" file
^ means beginning of the line, $ means end of the line.
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
add a comment |
- b - word border
grep -v "b0b"
- match beginning of line, your pattern and end of line
grep -v "^0$"
- or as @Sparhawk suggested -vx lineregexp
-w works, but in your case 0.2 are two words because dot character is a word separator.
answered 22 mins ago
Jakub JindraJakub Jindra
817
grep -v "b0b"doesn't really work here. What version of grep do you use?
– Arkadiusz Drabczyk
19 mins ago
add a comment |
grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.
Using sed is a bit easy in this context to just remove the whole words that match
sed '/^0$/d' file
answered 10 mins ago
InianInian
4,4851025
add a comment |
When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:
grep "^0$"
This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.
I hope this helps!
answered 10 mins ago
majesticLSDmajesticLSD
423
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
grep -vx 0
From man grep:
-x, --line-regexp
Select only those matches that exactly match the whole line.
For a regular expression pattern, this is like parenthesizing
the pattern and then surrounding it with ^ and $.
-w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".
answered 26 mins ago
SparhawkSparhawk
9,74264094
add a comment |
grep -vx 0
From man grep:
-x, --line-regexp
Select only those matches that exactly match the whole line.
For a regular expression pattern, this is like parenthesizing
the pattern and then surrounding it with ^ and $.
-w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".
answered 26 mins ago
SparhawkSparhawk
9,74264094
add a comment |
grep -vx 0
From man grep:
-x, --line-regexp
Select only those matches that exactly match the whole line.
For a regular expression pattern, this is like parenthesizing
the pattern and then surrounding it with ^ and $.
-w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".
answered 26 mins ago
SparhawkSparhawk
9,74264094
grep -vx 0
From man grep:
-x, --line-regexp
Select only those matches that exactly match the whole line.
For a regular expression pattern, this is like parenthesizing
the pattern and then surrounding it with ^ and $.
-w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".
answered 26 mins ago
SparhawkSparhawk
9,74264094
answered 26 mins ago
SparhawkSparhawk
9,74264094
answered 26 mins ago
SparhawkSparhawk
9,74264094
answered 26 mins ago
SparhawkSparhawk
9,74264094
9,74264094
add a comment |
add a comment |
With grep:
grep -v "^0$" file
^ means beginning of the line, $ means end of the line.
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
add a comment |
With grep:
grep -v "^0$" file
^ means beginning of the line, $ means end of the line.
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
add a comment |
With grep:
grep -v "^0$" file
^ means beginning of the line, $ means end of the line.
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
With grep:
grep -v "^0$" file
^ means beginning of the line, $ means end of the line.
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
answered 25 mins ago
Arkadiusz DrabczykArkadiusz Drabczyk
7,95521734
7,95521734
add a comment |
add a comment |
- b - word border
grep -v "b0b"
- match beginning of line, your pattern and end of line
grep -v "^0$"
- or as @Sparhawk suggested -vx lineregexp
-w works, but in your case 0.2 are two words because dot character is a word separator.
answered 22 mins ago
Jakub JindraJakub Jindra
817
grep -v "b0b"doesn't really work here. What version of grep do you use?
– Arkadiusz Drabczyk
19 mins ago
add a comment |
- b - word border
grep -v "b0b"
- match beginning of line, your pattern and end of line
grep -v "^0$"
- or as @Sparhawk suggested -vx lineregexp
-w works, but in your case 0.2 are two words because dot character is a word separator.
answered 22 mins ago
Jakub JindraJakub Jindra
817
grep -v "b0b"doesn't really work here. What version of grep do you use?
– Arkadiusz Drabczyk
19 mins ago
add a comment |
- b - word border
grep -v "b0b"
- match beginning of line, your pattern and end of line
grep -v "^0$"
- or as @Sparhawk suggested -vx lineregexp
-w works, but in your case 0.2 are two words because dot character is a word separator.
answered 22 mins ago
Jakub JindraJakub Jindra
817
- b - word border
grep -v "b0b"
- match beginning of line, your pattern and end of line
grep -v "^0$"
- or as @Sparhawk suggested -vx lineregexp
-w works, but in your case 0.2 are two words because dot character is a word separator.
answered 22 mins ago
Jakub JindraJakub Jindra
817
answered 22 mins ago
Jakub JindraJakub Jindra
817
answered 22 mins ago
Jakub JindraJakub Jindra
817
answered 22 mins ago
Jakub JindraJakub Jindra
817
817
grep -v "b0b"doesn't really work here. What version of grep do you use?
– Arkadiusz Drabczyk
19 mins ago
add a comment |
grep -v "b0b"doesn't really work here. What version of grep do you use?
– Arkadiusz Drabczyk
19 mins ago
grep -v "b0b" doesn't really work here. What version of grep do you use?– Arkadiusz Drabczyk
19 mins ago
grep -v "b0b" doesn't really work here. What version of grep do you use?– Arkadiusz Drabczyk
19 mins ago
add a comment |
grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.
Using sed is a bit easy in this context to just remove the whole words that match
sed '/^0$/d' file
answered 10 mins ago
InianInian
4,4851025
add a comment |
grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.
Using sed is a bit easy in this context to just remove the whole words that match
sed '/^0$/d' file
answered 10 mins ago
InianInian
4,4851025
add a comment |
grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.
Using sed is a bit easy in this context to just remove the whole words that match
sed '/^0$/d' file
answered 10 mins ago
InianInian
4,4851025
grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.
Using sed is a bit easy in this context to just remove the whole words that match
sed '/^0$/d' file
answered 10 mins ago
InianInian
4,4851025
answered 10 mins ago
InianInian
4,4851025
answered 10 mins ago
InianInian
4,4851025
answered 10 mins ago
InianInian
4,4851025
4,4851025
add a comment |
add a comment |
When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:
grep "^0$"
This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.
I hope this helps!
answered 10 mins ago
majesticLSDmajesticLSD
423
add a comment |
When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:
grep "^0$"
This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.
I hope this helps!
answered 10 mins ago
majesticLSDmajesticLSD
423
add a comment |
When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:
grep "^0$"
This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.
I hope this helps!
answered 10 mins ago
majesticLSDmajesticLSD
423
When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:
grep "^0$"
This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.
I hope this helps!
answered 10 mins ago
majesticLSDmajesticLSD
423
edited 4 mins ago
answered 10 mins ago
majesticLSDmajesticLSD
423
answered 10 mins ago
majesticLSDmajesticLSD
423
answered 10 mins ago
majesticLSDmajesticLSD
423
423
add a comment |
add a comment |
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