How to calculate partition Start End Sector?
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I am wondering what Start and End value to choose when partitioning my ext. SSD using fdisk
.
fdisk
suggests 2048-250069679, default 2048
but 250069679 cannot be divided by 512 nor by 2048. Wouldn't it be better to set the Start and End value to a number that can be devided by 512 or 2048 or 4096?
For example: Start 4096 and End 250068992
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Command (m for help): n
Partition type
p primary (0 primary, 0 extended, 4 free)
e extended (container for logical partitions)
Select (default p): p
Partition number (1-4, default 1):
First sector (2048-250069679, default 2048):
Last sector, +sectors or +size{K,M,G,T,P} (2048-250069679, default 250069679):
Created a new partition 1 of type 'Linux' and of size 119,2 GiB.
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
mkfs.ext4 /dev/sda1
mke2fs 1.43.4 (31-Jan-2017)
Ein Dateisystems mit 31258454 (4k) Blöcken und 7815168 Inodes wird erzeugt.
UUID des Dateisystems: fdce9286-4545-447c-9cca-7d67f5bb9f43
Superblock-Sicherungskopien gespeichert in den Blöcken:
32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208,
4096000, 7962624, 11239424, 20480000, 23887872
fdisk -l
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
And how can it be that the Sectors number is lower than the End value?
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
hard-disk fdisk external-hdd mkfs
add a comment |
I am wondering what Start and End value to choose when partitioning my ext. SSD using fdisk
.
fdisk
suggests 2048-250069679, default 2048
but 250069679 cannot be divided by 512 nor by 2048. Wouldn't it be better to set the Start and End value to a number that can be devided by 512 or 2048 or 4096?
For example: Start 4096 and End 250068992
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Command (m for help): n
Partition type
p primary (0 primary, 0 extended, 4 free)
e extended (container for logical partitions)
Select (default p): p
Partition number (1-4, default 1):
First sector (2048-250069679, default 2048):
Last sector, +sectors or +size{K,M,G,T,P} (2048-250069679, default 250069679):
Created a new partition 1 of type 'Linux' and of size 119,2 GiB.
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
mkfs.ext4 /dev/sda1
mke2fs 1.43.4 (31-Jan-2017)
Ein Dateisystems mit 31258454 (4k) Blöcken und 7815168 Inodes wird erzeugt.
UUID des Dateisystems: fdce9286-4545-447c-9cca-7d67f5bb9f43
Superblock-Sicherungskopien gespeichert in den Blöcken:
32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208,
4096000, 7962624, 11239424, 20480000, 23887872
fdisk -l
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
And how can it be that the Sectors number is lower than the End value?
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
hard-disk fdisk external-hdd mkfs
Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
have you considered using a higher level (therefore easier to use) tool, such asgparted
?
– ctrl-alt-delor
20 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
Live OS (boot off of USB, usessh -X
and run it remotely, orparted
.
– ctrl-alt-delor
15 hours ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the toolsfdisk
andmkfs.ext4
incorrect?
– AlexOnLinux
14 mins ago
add a comment |
I am wondering what Start and End value to choose when partitioning my ext. SSD using fdisk
.
fdisk
suggests 2048-250069679, default 2048
but 250069679 cannot be divided by 512 nor by 2048. Wouldn't it be better to set the Start and End value to a number that can be devided by 512 or 2048 or 4096?
For example: Start 4096 and End 250068992
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Command (m for help): n
Partition type
p primary (0 primary, 0 extended, 4 free)
e extended (container for logical partitions)
Select (default p): p
Partition number (1-4, default 1):
First sector (2048-250069679, default 2048):
Last sector, +sectors or +size{K,M,G,T,P} (2048-250069679, default 250069679):
Created a new partition 1 of type 'Linux' and of size 119,2 GiB.
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
mkfs.ext4 /dev/sda1
mke2fs 1.43.4 (31-Jan-2017)
Ein Dateisystems mit 31258454 (4k) Blöcken und 7815168 Inodes wird erzeugt.
UUID des Dateisystems: fdce9286-4545-447c-9cca-7d67f5bb9f43
Superblock-Sicherungskopien gespeichert in den Blöcken:
32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208,
4096000, 7962624, 11239424, 20480000, 23887872
fdisk -l
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
And how can it be that the Sectors number is lower than the End value?
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
hard-disk fdisk external-hdd mkfs
I am wondering what Start and End value to choose when partitioning my ext. SSD using fdisk
.
fdisk
suggests 2048-250069679, default 2048
but 250069679 cannot be divided by 512 nor by 2048. Wouldn't it be better to set the Start and End value to a number that can be devided by 512 or 2048 or 4096?
For example: Start 4096 and End 250068992
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Command (m for help): n
Partition type
p primary (0 primary, 0 extended, 4 free)
e extended (container for logical partitions)
Select (default p): p
Partition number (1-4, default 1):
First sector (2048-250069679, default 2048):
Last sector, +sectors or +size{K,M,G,T,P} (2048-250069679, default 250069679):
Created a new partition 1 of type 'Linux' and of size 119,2 GiB.
Command (m for help): p
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
mkfs.ext4 /dev/sda1
mke2fs 1.43.4 (31-Jan-2017)
Ein Dateisystems mit 31258454 (4k) Blöcken und 7815168 Inodes wird erzeugt.
UUID des Dateisystems: fdce9286-4545-447c-9cca-7d67f5bb9f43
Superblock-Sicherungskopien gespeichert in den Blöcken:
32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208,
4096000, 7962624, 11239424, 20480000, 23887872
fdisk -l
Disk /dev/sda: 119,2 GiB, 128035676160 bytes, 250069680 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0xa4b57300
Device Boot Start End Sectors Size Id Type
/dev/sda1 2048 250069679 250067632 119,2G 83 Linux
And how can it be that the Sectors number is lower than the End value?
Command (m for help): i
Selected partition 1
Device: /dev/sda1
Start: 2048
End: 250069679
Sectors: 250067632
Cylinders: 15566
Size: 119,2G
Id: 83
Type: Linux
Start-C/H/S: 0/32/33
End-C/H/S: 206/29/63
hard-disk fdisk external-hdd mkfs
hard-disk fdisk external-hdd mkfs
asked 21 hours ago
AlexOnLinuxAlexOnLinux
1686
1686
Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
have you considered using a higher level (therefore easier to use) tool, such asgparted
?
– ctrl-alt-delor
20 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
Live OS (boot off of USB, usessh -X
and run it remotely, orparted
.
– ctrl-alt-delor
15 hours ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the toolsfdisk
andmkfs.ext4
incorrect?
– AlexOnLinux
14 mins ago
add a comment |
Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
have you considered using a higher level (therefore easier to use) tool, such asgparted
?
– ctrl-alt-delor
20 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
Live OS (boot off of USB, usessh -X
and run it remotely, orparted
.
– ctrl-alt-delor
15 hours ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the toolsfdisk
andmkfs.ext4
incorrect?
– AlexOnLinux
14 mins ago
Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
have you considered using a higher level (therefore easier to use) tool, such as
gparted
?– ctrl-alt-delor
20 hours ago
have you considered using a higher level (therefore easier to use) tool, such as
gparted
?– ctrl-alt-delor
20 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
Live OS (boot off of USB, use
ssh -X
and run it remotely, or parted
.– ctrl-alt-delor
15 hours ago
Live OS (boot off of USB, use
ssh -X
and run it remotely, or parted
.– ctrl-alt-delor
15 hours ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the tools
fdisk
and mkfs.ext4
incorrect?– AlexOnLinux
14 mins ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the tools
fdisk
and mkfs.ext4
incorrect?– AlexOnLinux
14 mins ago
add a comment |
1 Answer
1
active
oldest
votes
Alignment doesn’t matter for the end sector. Sectors are numbered from 0; fdisk
is suggesting the last sector on your disk (which has 250069680 sectors).
Start: 2048
End: 250069679
Sectors: 250067632
is correct, 250069679 minus 2048 plus one is 250067632: the partition contains 250067632 sectors, starting at offset 2048.
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
add a comment |
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1 Answer
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votes
Alignment doesn’t matter for the end sector. Sectors are numbered from 0; fdisk
is suggesting the last sector on your disk (which has 250069680 sectors).
Start: 2048
End: 250069679
Sectors: 250067632
is correct, 250069679 minus 2048 plus one is 250067632: the partition contains 250067632 sectors, starting at offset 2048.
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
add a comment |
Alignment doesn’t matter for the end sector. Sectors are numbered from 0; fdisk
is suggesting the last sector on your disk (which has 250069680 sectors).
Start: 2048
End: 250069679
Sectors: 250067632
is correct, 250069679 minus 2048 plus one is 250067632: the partition contains 250067632 sectors, starting at offset 2048.
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
add a comment |
Alignment doesn’t matter for the end sector. Sectors are numbered from 0; fdisk
is suggesting the last sector on your disk (which has 250069680 sectors).
Start: 2048
End: 250069679
Sectors: 250067632
is correct, 250069679 minus 2048 plus one is 250067632: the partition contains 250067632 sectors, starting at offset 2048.
Alignment doesn’t matter for the end sector. Sectors are numbered from 0; fdisk
is suggesting the last sector on your disk (which has 250069680 sectors).
Start: 2048
End: 250069679
Sectors: 250067632
is correct, 250069679 minus 2048 plus one is 250067632: the partition contains 250067632 sectors, starting at offset 2048.
edited 20 hours ago
answered 21 hours ago
Stephen KittStephen Kitt
180k25408487
180k25408487
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
add a comment |
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
i am wondering why the end-value is not important. do you know why perhaps?
– AlexOnLinux
18 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@AlexOnLinux your choices are either to use all the sectors available or not. If you want them all and the disk has a size which is not a multiple of 512/2048/4096 then the end will not be aligned.
– icarus
13 hours ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
@icarus Having the Start and End aligned gives any performance advantages? Is it usefull to properly align the End-value when using multiple partitions?
– AlexOnLinux
10 mins ago
add a comment |
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Sectors is End minus Start. Usually for alignment, only Start matters.
– frostschutz
21 hours ago
have you considered using a higher level (therefore easier to use) tool, such as
gparted
?– ctrl-alt-delor
20 hours ago
@ctrl-alt-delor normaly i use gparted, but this time i have no gui installed.
– AlexOnLinux
18 hours ago
Live OS (boot off of USB, use
ssh -X
and run it remotely, orparted
.– ctrl-alt-delor
15 hours ago
@ctrl-alt-delor first: it's a raspberry pi using raspbian lite without gui. second: whats the problem of understanding how to properly align third: did i use the tools
fdisk
andmkfs.ext4
incorrect?– AlexOnLinux
14 mins ago